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What is the value of the equilibrium constant for the following reaction ach  at 25...

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xkat123 | Student, Undergraduate | Honors

Posted July 3, 2013 at 5:03 AM via web

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What is the value of the equilibrium constant for the following reaction ach  at 25 degree C?

 Ni(s) and Ag^+

 

 

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llltkl | College Teacher | Valedictorian

Posted July 3, 2013 at 6:16 AM (Answer #1)

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The relation between `E^0` and the equilibrium constant K is given by

`nFE^0=RTlnK`

`rArr lnK=(nFE^0)/(RT)`

Here, relevant `E^0` values are:

Ni(s) → Ni^(2+) +2e- (`E^0=0.25` V)

and Ag^+ + e- → Ag(s) (`E^0=0.80` V) *2

2Ag^+ + 2e- → 2Ag(s) (`E^0=0.80` V)

`E^0` (overall) = 0.80+0.25 = 1.05 V

Plugging in the valuesin the relation of K,

`lnK= (2*96485*1.05)/(8.314*298)`

`=81.78`

`rArr K =3.26*10^35`

Hence the value of equilibrium constant for the reaction between Ni(s) and `Ag^+` is `3.26*10^35` .

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