# What is the value of delta H for a reaction if the value of K doubles when the temperature is increased from 25 degrees Celsius to 35 degrees Celsius?

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We have the thermodynamic relationship:

lnK = - 'delta'H/RT + 'Delta'S/R

which yields: ln Kf/Ki = delta H/R [Tf - Ti]/[Tf.Ti]

or delta H = Rln Kf/Ki x [Tf.Ti]/[Tf - Ti]

= 8.314 ln 2 x [308x298]/[308-298] Joules

= 52.894 KJ