1 Answer | Add Yours
We have two resistors connected parallel here. So across each of the two resistors we have voltage of 10V.
For R1 using V = IR;
`10 = Ixx5xx10^3`
`I = 10/(5000) = 0.002A = 2mA`
So the total current of the circuit is` (2+10) = 12mA = 0.012A`
Power of a circuit is given by P = VI
`P = 10xx0.012`
`P = 0.12W`
So the power of the circuit is 0.12W.
We’ve answered 396,506 questions. We can answer yours, too.Ask a question