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What is the solution of x^2 - 2x + 1 = 0

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x32 | Student | (Level 1) eNoter

Posted January 2, 2013 at 5:14 AM via web

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What is the solution of x^2 - 2x + 1 = 0

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted January 2, 2013 at 5:16 AM (Answer #1)

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The equation x^2 - 2x + 1 = 0 has to be solved for x.

x^2 - 2x + 1 = 0

=> x^2 - x - x + 1 = 0

=> x(x - 1) - 1(x - 1) = 0

=> (x - 1)(x - 1) = 0

This gives the roots of the equation {1, 1}

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user1670897 | (Level 1) eNoter

Posted January 2, 2013 at 8:45 AM (Answer #2)

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x^2 - 2x + 1 = 0

=> (x - 1)^2 = 0

=> x = 1

The answere is 1

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redranger2 | Student, Grade 9 | (Level 1) eNoter

Posted January 27, 2013 at 11:03 AM (Answer #3)

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Using Completeing the Square

x^2-2x+1=0

x^2-2x=-1

x^2-2x+(2/2)^2=-1+(2/2)^2

x^2-2x+1^2=-1+1

Using the identity a^2-2ab+b^2=(a-b)^2

(x-1)^2=0

`sqrt(x-1^2)` =`sqrt(0)`

x-1=0

x=1

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