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What is the solution for in and out table, 1 in 2 out, 2 in 4 out, 3 in 7 out, 4 in ?...

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lukenac | Student, Grade 9 | eNotes Newbie

Posted March 3, 2009 at 9:38 AM via web

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What is the solution for in and out table, 1 in 2 out, 2 in 4 out, 3 in 7 out, 4 in ? out, 5 in and ? out.

 

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kmieciakp | High School Teacher | Valedictorian

Posted March 3, 2009 at 11:42 PM (Answer #1)

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11 and 16-- add the in to the out before it--

1+1=2; 2+2=4; 3+4=7; 4+7=11; 5+11=16

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rakesh05 | High School Teacher | (Level 1) Assistant Educator

Posted May 21, 2013 at 8:40 AM (Answer #3)

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In          1          2       3          4         5

out         2         4       7           --       --

From the above pattern we observe that every successive out term is a sum of  previous out+current In.

i.e.       the secon out 4= first out 2+second In 2

           the third out 7= second out 4+third in 3

          the fourth out =third out 7+ fourth In 4

                                =11

            the fifth out= fourth out 11+ fifth In 5

                              =16.

So,      the numbers are    11 and 16.

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ricrobrod | Elementary School Teacher | eNoter

Posted June 15, 2010 at 2:53 PM (Answer #2)

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in   1   2   3    4    5

out   2   4   7   11  16

If you add the 'out' number to the following 'in' number, you will get the next 'out' number. So, 2+2=4, 4+3=7, 7+4=11, 11+5=16. Your solution is 11 and 16.

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