What is the solution for in and out table, 1 in 2 out, 2 in 4 out, 3 in 7 out, 4 in ? out, 5 in and ? out.

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11 and 16-- add the in to the out before it--

1+1=2; 2+2=4; 3+4=7; 4+7=11; 5+11=16

In 1 2 3 4 5

out 2 4 7 -- --

From the above pattern we observe that every successive out term is a sum of previous out+current In.

i.e. the secon out 4= first out 2+second In 2

the third out 7= second out 4+third in 3

the fourth out =third out 7+ fourth In 4

=11

the fifth out= fourth out 11+ fifth In 5

=16.

So, the numbers are 11 and 16.

in 1 2 3 4 5

out 2 4 7 11 16

If you add the 'out' number to the following 'in' number, you will get the next 'out' number. So, 2+2=4, 4+3=7, 7+4=11, 11+5=16. Your solution is 11 and 16.

1 2 3 4 5

2 4 7 11 16

The reason I got those numbers is because it seems like the in is being added to the previous out:

like:

2+2=4

4+3=7

7+4=11

11+5=16

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