# What is the solution of 3x^2 - 6x + 7 = 0

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The solution of a quadratic equation ax^2 + bx + c = 0 is `(-b+-sqrt(b^2 - 4ac))/(2a)`

For the equation 3x^2 - 6x + 7 = 0 the solution is `(6+-sqrt(36-84))/(6) = 1 +- (2/sqrt 3)*i`

The solution of the equation 3x^2 - 6x + 7 = 0 is `1 +- (2/sqrt 3)*i`

ericmilamattim | (Level 1) Honors

Posted on

1. by factoring

2. completing the square

For any quadratic equation in the form of ax^2 + bx + c = 0

x=  `(-b+-sqrt(b^2 - 4ac))/(2a)`

so, for the equation  3x^2 - 6x + 7 = 0   the solution is

x= `(-(-6)+-sqrt((36) - 84))/6`

`x=1+-(2/sqrt(3))*i`

meaning there is no real solution only imaginary.

I hope this helps!

ericmilamattim | (Level 1) Honors

Posted on

1. by factoring

2. completing the square

For any quadratic equation in the form of ax^2 + bx + c = 0

x=

so, for the equation  3x^2 - 6x + 7 = 0   the solution is

meaning there is no real solution only imaginary.

I hope this helps!