# What is the solution of 3x + 2y = 7 and 2x + 3y = 1

thilina-g | College Teacher | (Level 1) Educator

Posted on

Here is a more suitable method of solving simultaneous equations than simple substiution.

`3x + 2y = 7`

`2x + 3y = 1`

Multiply 1st equation by 2 and multiply second equation by 3 and substract them.

`2(3x + 2y) -3(2x + 3y) = 2 xx 7 - 3 xx 1`

`6x+4y-6x-9y = 14-3`

`-5y = 11`

`y = -11/5`

You can use this in second equation,

`2x+3(-11/5) = 1`

`2x - 33/5 = 1`

`2x = 1+33/5`

`2x = (5+33)/5`

`2x = 38/5`

`x = 19/5`

This gives `x = 19/5` and `y = -11/5`

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The set of linear equations 3x + 2y = 7 and 2x + 3y = 1 has to be solved.

3x + 2y = 7

=> `x = (7 - 2y)/3`

substitute in 2x + 3y = 1

=> `(2/3)*(7 - 2y) + 3y = 1`

=> `2(7 - 2y) = 3(1-3y)`

=> 14 - 4y = 3 - 9y

=> 5y = -11

=> y = -11/5

x = `(7 + 22/5)/3 = 57/15 = 19/5`

The solution of the set of equations is x = `19/5` and y = `-11/5`

Wiggin42 | Student, Undergraduate | (Level 2) Valedictorian

Posted on

(1) 3x + 2y = 7
(2) 2x + 3y = 1

(1) x 2:
6x + 4y = 14

(2) x 3:
6x + 9y = 3

Subtract the two equations:

6x + 9y = 3
-  6x + 4y = 14
-----------------------
5y = 11

Solve for y, plug back in to solve for x.

jess1999 | Student, Grade 9 | (Level 1) Valedictorian

Posted on

3x + 2y = 7

2x + 3y = 1

First multiply everything in the top equation by 2, and everything in the second equation by 3

6x + 4y = 14

6x + 9y = 3    now subtract 6x with 6x ( which means subtract 4y with 9y and 14 with 3 )

By subtracting, you should get

-5y = 11 divide both sides by -5

By dividing, you should get

Now plug -11/5 into one of the equation

2x + 3 ( -11/5 ) = 1 Multiply 3 with -11/5

By multiplying your equation should look like

2x - 33/5 = 1 add -33/5 on both sides