What is the solution of 3x^2 + 4x + 10 = 0

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The solution of a quadratic equation of the form ax^2 + bx + c = 0 is `x1 = (-b + sqrt(b^2 - 4ac))/(2a)` and x2 = (-b - sqrt(b^2 - 4ac))/(2a).

For the given equation, a = 3, b = 4 and c = 10, this gives the roots as:

`x1 = (-4 + sqrt(16 - 120))/ 6`

=> `-2/3 + i*sqrt 26/6`

and `x2 = -2/3 - i*sqrt 26/6`

**The solution set of the equation is `{-2/3 + i*(sqrt 26)/6, -2/3 + (i*sqrt 26)/6}` **

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