What is the solution for: |2x – 3| – 8 = –1

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The absolute value |x| is defined as -x if x<0 and x if x>=0.

We are given that |2x – 3| – 8 = –1

=> (2x – 3) – 8 = –1 and -(2x – 3) – 8 = –1

=> 2x - 3 - 8 = -1 and -2x + 3 - 8 = -1

=> 2x - 11 = -1 and -2x - 5 = -1

=> x = 10/2 and 2x = -4

=> x = 5 and x = -2

**The solution is x = 5 and x = -2**

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