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The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz....
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The relationship for wavespeed and the properties of a wave are given by the relationships
S = df where S is speed, d is the distance traveled, and f is frequency
S = d/T where T is the period
S = Wf where W is the wavelength
and S = W/T
For this given problem we can find the minimum and maximum wavelengths rearranging the S = Wf equation.
W = S/f
for the lowest note of 45 Hz (45/second) we get W = (343m/s)/(45/s) = 7.62 m
for the highest note of 375Hz (375/seconds) we get
W=(343m/s)/(375/s) = 0.915 m.
Therefore the range of wavelengths is between 0.915m to 7.62m.
Posted by mwmovr40 on April 12, 2012 at 12:18 AM (Answer #1)
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