What is the slope of a line that that is perpendicular to a line that passes throudg (-2,-2) and (1,3)?

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First we will find the slope of the line that passes through the points (-2,-2) and (1,3)

==>The slope (m1)= (y2-y1)/(x2-x1) = (3-(-2))/(1-(-2)) = 5/3

Now let the slope of the perpendicular line be m2.

Then we know that the product of the slopes of two perpendicular lines is -1.

==> m1 X m2 = -1

But we know that m1 = 5/3

==> 5/3 X m2 = -1

Now we will multiply both sides by 3/5

==> m2 = -1 (3/5) = -3/5

**Then, the slope of the perpendicular line is -3/5**

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