# What is the slope of the line that passes through points (5,-8) and (3,-3), and is the line through (5,-8) and (3,-3) horizontal, vertical, or oblique?

### 2 Answers | Add Yours

(A.) To determine the slope of a line which passes through `(x_1,y_1)` and `(x_2, y_2)` , use the formula :

`m = (y_2-y_1)/(x_2-y_2)`

Let point1 be (3,-3) and point2 be (5,-8).

`m= (-8-(-3))/(5-3) = (-8+3)/(5-3)=-5/2`

**Hence, slope of the line is -5/2.**

(B.) Note that for a horizontal line, the slope is zero. Let's say, if we have points (2,3) and (7,3). The slope of this is:

`m = (3-3)/(7-2) = 0/7 = 0`

Since m is zero, the line passing through these points is a horizontal line.

Whereas, a vertical line has no slope. For example if we have points (5,1) and (5,4), the slope is:

`m = (4-1)/(5-5)=3/0`

In fraction, we could not have a zero as a denominator. Hence, m is undefined and the line passing through (5,1) and (5,4) is vertical.

And for an oblique line, the value of the slope *m* is any real numbers except zero.

**Since the points (5,-8) and (3,-3) has a slope equal to -5/4, then, the line containing these points is oblique.**

A.) To determine the slope of a line which passes through (5,-8)and (3,-3) you can use the formula

Let point1 be (3,-3) and point2 be (5,-8). Which will result in m=-5/2

**Meaning the slope of the line is -5/2. Meaning for every two x it increases, it decreases by -5 ys.**

B. The line is oblique, its neither vertical or horizontal.

This because horizontal lines have a slope of 0.

Vertical lines have no slope, splope is the chage in y/ change in x and here we have no change in x. So the slope is undefined.

In oblique lines, the value of the slope *m* is all real numbers except zero.