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What is scalar product of a=2i-3j, b=6i+4j?
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Remember the formula of dot scalar product:
`bar a` * `barb` = |bara|*|barb|*cos theta
theta is the angle between bara and barb
|a| is the magnitude of the vector a: bara = sqrt(2^2 + (-3)^2)
bara = sqrt 13
|b| is the magnitude of the vector b:
`barb = sqrt(6^2 + 4^2)` `bara = sqrt 52 = 2sqrt13`
`` `bara*barb = (sqrt13)*(2sqrt13) cos theta`
The scalar product is `bara*barb` =26 cos `theta` .
Posted by sciencesolve on December 4, 2011 at 12:08 AM (Answer #1)
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