# What are the roots of the equation 3x^2 + 2x + 1 = 0

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The roots of a quadratic equation ax^2 + bx + c = 0 are `(-b+-sqrt(b^2-4ac))/(2a)`

For the equation 3x^2 + 2x + 1 = 0, a = 3, b = 2 and c = 1. The roots of the equation are:

`(-2 +- sqrt(2^2 - 4*3*1))/(2*3)`

= `(-2 +- sqrt(4 - 12))/6`

= `(-2 +- i*sqrt 8)/6`

= `-1/3 +- i*sqrt 2/3`

**The roots of the equation `3x^2 + 2x + 1 = 0` are **`-1/3 +- i*sqrt 2/3`