Homework Help

What are the roots of 24x^3+18x^2-168x=0  

user profile pic

susan1988 | Student, Undergraduate | (Level 1) Honors

Posted February 17, 2011 at 1:00 PM via web

dislike 0 like

What are the roots of 24x^3+18x^2-168x=0

 

1 Answer | Add Yours

user profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted February 17, 2011 at 1:08 PM (Answer #1)

dislike -2 like

We have to solve 24x^3 + 18x^2 - 168x = 0

24x^3 + 18x^2 - 168x = 0

=> 6x( 4x^2 + 3x – 28) = 0

x1 = 0

x2 = [-3 + sqrt ( 9 + 448)]/8

=> [ -3 + sqrt 457]/8

=> -3/8 + sqrt 457 / 8

x3 = -3/8 – sqrt 457/8

The required roots of the equation are 0 , -3/8 + sqrt 457/8 and -3/8 – sqrt 457/8

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes