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What is range of f(x) = 2sin5x +5?
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You need to use the following information with respect to the range of sine function, such that:
`y = sin alpha in [-1,1]`
Considering `alpha = 5x` yields:
`y = sin 5x in [-1,1] => -1 <= sin 5x <= 1`
You need to multiply by 2 such that:
`-2 <= 2sin 5x <= 2`
Adding 5 all over, yields:
`-2 + 5 <= 2sin 5x + 5 <= 2 + 5`
`3 <= 2sin 5x + 5 <= 7 => y in [3,7]`
Hence, evaluating the range of the given function y = 2sin 5x + 5, yields `y in [3,7].`
Posted by sciencesolve on July 7, 2013 at 3:57 PM (Answer #1)
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