# What is the probability the spinner stops on:1) 32) number less than 43) even numberThe sample space for the spinner is (1,2,3,4,5,6)Please help me find the probability for each question.

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There are six possibilities for where the spinner will stop. To figure out any particular chance, count how many times out of 6 it could happen.

1) Any one number -- such as 3 -- has a probability of 1 in 6 or 1/6.

2) There are three numbers less than four, so the probability of landing on one of them is 3 in 6, or 1/2.

3) The same is true of landing on an even number. There are three possible stopping places that are even, so the probability is 3 in 6 or 1/2 again.

1.) There is only one number 3 on your spinner out of 6 total. This will make your probability 1/6.

2.) There are 3 numbers less than 4 on the spinner out of 6 total numbers. This gives you the probability of 3/6 or 1/2.

3.) There are 3 even numbers out of 6, which makes the probability 3/6 or 1/2.

1) There is one 3 in the range, and there is six numbers in the sample space, so **P= 1/6**

2) There is 3 numbers less than 4 which is 1,2 and 3, so **P= 3/6=1/2**

3)There is three even numbers 2,4 and 6 so **P= 3/6 = 1/2**

** 1)** you have six numbers and one of them is three so you would have

*of a chance to get three*

**1/6**** 2) **infering that number doesn't include 4 you would have

**(3/6) of a chance**

*1/2*

* 3)* to get a even number (2,4,6) you would have

*(3/6) of a chance*

**1/2**I think it is 3 bacause the spinner could land on even numbers

or it can land on all the numbers