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There are six possibilities for where the spinner will stop. To figure out any particular chance, count how many times out of 6 it could happen.
1) Any one number -- such as 3 -- has a probability of 1 in 6 or 1/6.
2) There are three numbers less than four, so the probability of landing on one of them is 3 in 6, or 1/2.
3) The same is true of landing on an even number. There are three possible stopping places that are even, so the probability is 3 in 6 or 1/2 again.
1.) There is only one number 3 on your spinner out of 6 total. This will make your probability 1/6.
2.) There are 3 numbers less than 4 on the spinner out of 6 total numbers. This gives you the probability of 3/6 or 1/2.
3.) There are 3 even numbers out of 6, which makes the probability 3/6 or 1/2.
1) There is one 3 in the range, and there is six numbers in the sample space, so P= 1/6
2) There is 3 numbers less than 4 which is 1,2 and 3, so P= 3/6=1/2
3)There is three even numbers 2,4 and 6 so P= 3/6 = 1/2
1) you have six numbers and one of them is three so you would have 1/6 of a chance to get three
2) infering that number doesn't include 4 you would have 1/2 (3/6) of a chance
3) to get a even number (2,4,6) you would have 1/2 (3/6) of a chance
I think it is 3 bacause the spinner could land on even numbers
or it can land on all the numbers
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