What is the point of contact of y = 3x + 4 and 8x - 4y = 16

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The co-ordinates of the point at which the lines y = 3x + 4 and 8x - 4y = 16 intersect satisfies both the equations.

Substituting y = 3x + 4 in 8x - 4y = 16

=> 8x - 4(3x + 4) = 16

=> 8x - 12x - 16 = 16

=> -4x = 32

=> x = -8

y = -20

**The point of intersection of the lines is (-8, -20)**

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