What is the percentage yield for a reaction of benzene, C6H6 with chlorine, that produces chlorobenzene, C6H5Cl, and hydrogen chloride if 36.8 grams of benzene gives an actual yield of 38.8 grams...

What is the percentage yield for a reaction of benzene, C6H6 with chlorine, that produces chlorobenzene, C6H5Cl, and hydrogen chloride if 36.8 grams of benzene gives an actual yield of 38.8 grams of chlorobenzene?

 

Balanced equation-

1 C6H6 (l) + 1 Cl2 (g) -> 1 C6H5Cl (l) + 1 HCl (g) 

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jerichorayel | College Teacher | (Level 2) Senior Educator

Posted on

In computing for the percent yield of the reaction, we can use the expression:

`percent yield = (actual yield)/(theo retical yield) * 100`

actual yield = 38.8

theoretical yield  = ?

 

We can obtain the theoretical yield by stoichiometry. 

`36.8 grams C_6H_6 * (1 mol e C_6H_6)/(78.11 grams) * (1 mol e C_6H_5Cl)/(1 mol e C_6H_6) * (112.56)/(1 mol e C_6H_5Cl)`

`= 53.03 grams C_6H_5Cl`

 

Percentage yield:

`percent yield = (actual yield)/(theo retical yield) * 100`

`percent yield = (38.8)/(53.03) * 100`

percent yield = 73.2%

 

Sources:

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