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What is the percentage yield for a reaction of benzene, C6H6 with chlorine, that...

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persianimmortal | Student, Grade 12 | Valedictorian

Posted April 23, 2013 at 11:30 PM via web

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What is the percentage yield for a reaction of benzene, C6H6 with chlorine, that produces chlorobenzene, C6H5Cl, and hydrogen chloride if 36.8 grams of benzene gives an actual yield of 38.8 grams of chlorobenzene?

 

Balanced equation-

1 C6H6 (l) + 1 Cl2 (g) -> 1 C6H5Cl (l) + 1 HCl (g) 

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jerichorayel | College Teacher | (Level 1) Senior Educator

Posted April 24, 2013 at 12:22 AM (Answer #1)

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In computing for the percent yield of the reaction, we can use the expression:

`percent yield = (actual yield)/(theo retical yield) * 100`

actual yield = 38.8

theoretical yield  = ?

 

We can obtain the theoretical yield by stoichiometry. 

`36.8 grams C_6H_6 * (1 mol e C_6H_6)/(78.11 grams) * (1 mol e C_6H_5Cl)/(1 mol e C_6H_6) * (112.56)/(1 mol e C_6H_5Cl)`

`= 53.03 grams C_6H_5Cl`

 

Percentage yield:

`percent yield = (actual yield)/(theo retical yield) * 100`

`percent yield = (38.8)/(53.03) * 100`

percent yield = 73.2%

 

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