What is the ordered vertex pair, axis of symmetry, x-intercept, and y intercept for this problem f(x) = x^2 + 6x-16?
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Let y = f(x)
This is the equation of a parabola, X^2=4aY (where, X=(x+3) and Y=(y+25))
The vertex being at X=0, Y=0,
Thus, x+3=0, `rArr` x=-3,
y+25=0, `rArr` y=-25
Therefore the vertex is at (-3, -25).
Axis of symmetry may be obtained by putting X=0,
This is the equation of the axis of symmetry of the parabola.
The x-intercept is obtained by putting y=0,
So, there will be two x intercepts, 2 units and 8 units.
The y-intercept is obtained by putting x=0,
Therefore, y-intercept will be 16 units.
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