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What is the Na+ ion concentration in the solution formed by mixing 20. mL of 0.10 M...

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lak-86 | Student, Undergraduate | Salutatorian

Posted June 11, 2013 at 6:12 PM via web

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What is the Na+ ion concentration in the solution formed by mixing 20. mL of 0.10 M Na2SO4 solution with 50. mL of 0.30 M Na3PO4 solution?

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted June 11, 2013 at 6:30 PM (Answer #1)

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`Na_2SO_4 rarr 2Na^++SO_4^(2-)`

`Na_3PO_4 rarr 3Na^++PO_4^(3-)`

 

Mole ratio

`Na_2SO_4:Na^+ = 1:2`

`Na_3PO_4:Na^+ = 1:3`

 

Amount of `Na_2SO_4` used `= 0.1/1000xx20`

Amount of `Na^+` from `Na_2SO_4 = 0.1/1000xx20xx2`

 

Amount of `Na_3PO_4` used `= 0.3/1000xx50`

Amount of `Na^+` from `Na_3PO_4 = 0.3/1000xx50xx3`

 

Total `Na^+`  moles

= (`Na^+` from `Na_2SO_4` )+(`Na^+` from `Na_3PO_4` )

`= 0.1/1000xx20xx2+0.3/1000xx50xx3`

= 0.049

 

So this 0.049 moles of  `Na^+` is (20+50) = 70ml of solution.

 

Concentration of `Na^+ = 0.049/70xx1000 M = 0.7M`

 

So the final concentration of `Na^+` is 0.7M. 

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