Homework Help

What is the minimum value of x^2 - 8x + 32

user profile pic

tonyah995 | Student, Undergraduate | (Level 1) Salutatorian

Posted September 4, 2013 at 5:25 PM via web

dislike 0 like

What is the minimum value of x^2 - 8x + 32

1 Answer | Add Yours

user profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted September 4, 2013 at 5:27 PM (Answer #1)

dislike 1 like

The minimum value of x^2 - 8x + 32 has to be determined.

x^2 - 8x + 32

= x^2 - 8x + 16 + 16

= (x - 4)^2 + 16

The least value that (x - 4)^2 can take on is 0.

This gives the least value of x^2 - 8x + 32 as 16

Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes