What is the minimum value of x^2 - 8x + 32

Topic:

Math

Asked on

1 Answer | Add Yours

justaguide's profile pic

Posted on

The minimum value of x^2 - 8x + 32 has to be determined.

x^2 - 8x + 32

= x^2 - 8x + 16 + 16

= (x - 4)^2 + 16

The least value that (x - 4)^2 can take on is 0.

This gives the least value of x^2 - 8x + 32 as 16

We’ve answered 301,112 questions. We can answer yours, too.

Ask a question