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f '(x) = 3x^2 + 2*2x - 32.
f '(x) = 3x^2 + 4x - 32
We'll differentiate again the result f'(x), with respect to x and we'll get f "(x):
f "(x) = 6x+ 4.
Therefore, the double derivative is: f "(x) = 6x + 4.
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