What is log(base 2) 32?
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Since `log_ax=n` means that `a^n=x` we can write:
Since, the bases in the above equation are equal i.e 2, we can set the exponents equal. So,
Therefore, the value of `log_2(32)` is 5.
To determine the value of `log_(2)32`
we use the meaning of logarithms:`log_(a)b = x rArr a^x = b`
Therefore we let `log_(2)32 = x`` `
We rewrite as `2^x = 32`
Next, we'll rewrite 32 as a power of 2. 32 = `2^5` ` `
`2^x = 2^5`
Therefore x = 5 as we have the same base
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