# What is limit x -> 3 (x^3 - 27)/(x - 3)

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The limit `lim_(x->3) (x^3 - 27)/(x - 3)` has to be determined.

Substituting x = 3 gives the indeterminate form `0/0` . Use l'Hopital's rule and replace the numerator and denominator with their derivatives.

This gives:

`lim_(x->3) (x^3 - 27)/(x - 3)`

= `lim_(x->3) (3x^2)/(1)`

= 3*9

= 27

**The limit **`lim_(x->3) (x^3 - 27)/(x - 3) = 27`