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What is `lim_(x->oo)(x+7)/(x^2-8)`
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The limit `lim_(x->oo)(x+7)/(x^2 - 8)` has to be determined.
Substituting x = `oo` , gives the indeterminate form `oo/oo` . Using l'Hopital's rule substitute the numerator and denominator of the expression by their derivatives. This gives:
Substitute `x = oo`
The limit `lim_(x->oo)(x+7)/(x^2 - 8) = 0`
Posted by justaguide on August 26, 2013 at 3:09 PM (Answer #1)
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