What is the length of a segment with endpoints (-8,-3) and (-3,-8)?



Asked on

2 Answers | Add Yours

justaguide's profile pic

Posted on (Answer #1)

The length of a line segment between the points (x1, y1) and (x2, y2) is equal to sqrt[(x1 - x2)^2 + (y1 - y2)^2]

Substituting the points given we have x1 = -8, x2 = -3, y1 = -3 and y2 = -8.

The length of the line segment between them is sqrt[(-3 + 8)^2 + (-8 + 3)^2]

=> sqrt [ 25 + 25]

=> 5*sqrt 2

The length of the required segment is 5*sqrt 2

shaznl1's profile pic

Posted on (Answer #2)

the distance formula in a plane meaning the distance between two points and a plane is:

If two points are (x1,y1),(x2,y2)

distance= sqrt((x1-x2)^2+(y1-y2)^2)

well you could choose either of the two points as the (x1,y1) point

I will give the example of choosing (-8,-3) as the (x1,y1) point.

Thus, x1=-8, y1=-3, x2= -3, y2=-8

substitute all the values into the equations

distance = sqrt((-8+3)^2+(-3+8)^2)


sqrt 50

=5 sqrt2

The distance between the two points( the length of the line) with endpoints (-8,-3) and (-3,-8) is 5 sqrt2.

You could also make a graph and construct a right triangle to do this question.

We’ve answered 396,837 questions. We can answer yours, too.

Ask a question