What is the ionic equation of
NaOH + HCl -> H2O +NaCl
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`NaOH_(aq) + HCl_(aq) -> H2O_(l) + NaCl_(aq)`
Write the ionic form of the above reaction...
`(Na^+) + (OH^-) + (H^+) + (Cl^-) -> (H_2O) + (Na^+) + (Cl^-)`
Cancel out the exactly the terms from either side of the reaction..
Net Ionic Equation...
`(OH^-) + (H^+) -> H_2O`
Follow the link for rules to write net ionic equation.
Here the reaction is called as nutrilization reaction.
Tio write a net ionic equation, we must follow the follow rules
1. write the balanced reaction with their phrases
2. write the full ionic equation. only (aq) phrases will disassociate not solid, gas and liquid
3. remove the common ion, the resulting equation is the net ionic eqaution
for the reaction
NaOH (aq) + HCl(aq)=====> NaCl(aq) + H2O(l)
full ionic equation
Na(+)(aq) + OH(-)(aq) + H+(aq) + Cl(-)(aq)===> Na(+)(aq) + Cl(-)(aq) +H2O
net ionic equation:
H(+)(aq) + OH(-) (aq) ===> H2O(l)
[here water will be in liquid phase not in aqueous phase]
the full ionic equation for NaOH + HCl -> H2O +NaCl looks like:
`Na^+(aq) + OH^- (aq) + H^+ (aq) + Cl^- (aq) -gt Na^+ (aq) + Cl^- (aq) + H2O (l)`
When you cancel like terms in the equation you end up with the net ionic equation which is:
`OH^- (aq) + H^+ (aq) -> H2O (l)`
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