What is the internal resistance of a 12.0 V car battery whose terminal voltage drops to 8.4 V when the starter draws 75 A?

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Drop in Voltage =12-8.4=3.6 V

Cureent Draw= 75A

Let internal resistance be R ,the By Ohm's law,we have

V=IR

3.6=75 R

R=3.6/75=0.048 ohms

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