what is the integral of xe^2x ?



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jeew-m's profile pic

Posted on (Answer #1)

This should be soled as integrals by parts. In Integrals by parts it says if U and V are fuctions then,

`intUdv = UV-intVdu`

So let us take U= x and V=e^(2x)

Then by differentiation with respect to x;

dU/dx = 1

     dU = dx


dV/dx = 2e^(2x)

     dV = 2e^(2x) dx


By applying the intergration by parts;

`int(x*2e^(2x)) dx = x*e^(2x)-int(e^(2x)) dx`

`intx*e^(2x) dx =` (1/2)(`x*e^(2x)-int(e^(2x)) dx`)

                 =` (1/2)(x*e^(2x)-1/2*e^(2x))+C`


So the answer is;

`int(x*e^(2x)) dx ` = ` (1/2)(x*e^(2x)-1/2*e^(2x))+C`

Where C is a contant.



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