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What is the integral `int ln x/x dx`
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The integral `int ln x/x dx` has to be determined.
Let `ln x = t`
`dt/dx = 1/x => (1/x)* dx = dt`
`int ln x/x dx`
= `int t dt`
Substitute `t = ln x`
= `(ln x)^2/2`
The integral `int ln x/x dx = (ln x)^2/2 + C`
Posted by justaguide on June 30, 2013 at 4:22 PM (Answer #1)
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