WHAT IS THE INTEGRAL OF 1/e^-2y dy

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`int1/e^(-2y)dy=inte^(2y)dy`

`=(1/2)e^(2y)+c`

where c is integrating constant.

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`int1/e^(-2y)dy=inte^(2y)dy`

`=(1/2)e^(2y)+c`

where c is integrating constant.

Join a community of thousands of dedicated teachers and students.

Join eNotes