# What impulse does the force shown in the figure exert on a 250 g particle? The graph starts at (0, 1000). It is a constant line until (2, 1000) and then starts decreasing until the point (6,0). It...

What impulse does the force shown in the figure exert on a 250 g particle?

The graph starts at (0, 1000). It is a constant line until (2, 1000) and then starts decreasing until the point (6,0). It touches the x-axis at (6,0) and this is where the graph ends. The y-axis is in terms of F_x (N) and the x-axis is in terms of miliseconds (ms).

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You need to remember that the impulse represents the area under the graph given such that:

`I= int_0^6 F(t) dt`

Notice that you need to evaluate the area of a rectangle whose length is of 1000 N and width is of 2 ms and the area of right angle rectangle, whose horizontal leg is of 4 ms and vertical leg is of 1000 N such that:

`I = 1000*2 + (1000*4)/2 => I = 4000 gm/s => I = 4 (Kgm)/s`

**Hence, evaluating the impulse, under the given conditions, yields `I = 4 (Kgm)/s` .**