What is his mass in the Canal Zone? Answer in units of kg.
What is his weight in the Canal Zone? Answer in units of N.
A(n) 98.3 kg boxer has his first match in the Canal Zone with gravitational acceleration 9.782 m/s^2 and his second match at the North Pole with gravitational acceleration 9.832 m/s^2.
What is his mass at the North Pole? Answer in units of kg.
What is his weight at the North Pole? Answer in units of N.
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Mass is an invariant; that is, mass does not change from location to location. Therefore, the mass of the 98.3-kg boxer is 98.3 kg wherever he goes.
Weight is a force, and is calculated using Newton's Second Law as the product of mass and gravitational acceleration
W = m g
in which the mass is given in kilograms, the local acceleration of gravity in m/s^2, and the weight in kg m/s^2 or Newtons.
Using this equation, we find that the weight of the boxer at the North Pole is
W = ( 98.3 kg ) ( 9.782 m/s^2 ) = 961.57 Newtons
and his weight at the Canal Zone is
W = ( 98.3 kg ) ( 9.832 m/s^2 ) = 966.48 Newtons
Since the mass is given to three significant figures, we should express these results using only three significant figures as well. The weights are then 962 Newtons at the North Pole and 966 Newtons at the Canal Zone.
Mass of the boxer = 98.3 kg is given The gravitational acceleration g at the Canal zone 9.782m/s^2.
Weight is a force given by the product of mass and the gravitational acceleration , g of the place, or, w= m*g. Therefore, the weight changes and is higher it g increases or decreases if g decreases.
The weight of the boxer at the Canal zone = mass*g=98.3kg *9.782m/s^2=961.5706N.
Mass of the boxer is 98.3 kg at any place. Mass does not vary from place to place. Mass is not depending on gravitational acceleration. So his mass at the north pole is 98.3kg as given.
But his weight changes as gravitational accelerartion at the north pole is different and is given to be 9.832 m/s^2. So his weight is mass* gravitational acceleration = 98.3*9.832=966.4856N .
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