What is the general term of the following series 60/121, -30/11, + 15, - ... + 219615/16.

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justaguide | College Teacher | (Level 2) Distinguished Educator

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Th general term of the the series: 60/121, 30/11, 15 , ... 219615/16 has to be determined.

The difference of consecutive terms of the series is not equal, this is not an arithmetic progression.

But dividing each term of the series by the previous term gives a constant value.

(-30/11)/(60/121) = -5.5

15/(-30/11) = -5.5

The given series is a geometric progression with the first term 60/121 and common ratio -5.5.

The general term of the series is  tn = (60/121)*(-5.5)^(n - 1)

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