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`f'(x) = 12x^2+ 4x − 10`
To get the f(x) we have to integrate this.
`int(f'(x))dx = int (12x^2+4x-10)dx`
`f(x) = int (12x^2+4x-10)dx`
`f(x) = 4x^3+2x^2-10+C` where C is a constant.
So the answer is;
`f(x) = 4x^3+2x^2-10+C`
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