# What is (f o g)(36) if f(x)=6^x and g(x)=log6 x ?

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We are given that f(x)= 6^x and g(x) = log(6) x

We have to find fog(36)

fog(36) = f(g(36))

=> f(log(6) 36)

=> 6^(log (6) 36)

we know that a^(log(a) x) = x

=> 36

**The required solution for fog(36) = 36**

According to the rule, (f o g)(x) = f(g(x))

So, (f o g)(36) = f(g(36))

We'll calculate g(36) = log6 (36) = log6 (6^2) = 2*log6 (6) = 2

(f o g)(36) = f(g(36)) = f(2)

We'll substitute x by 2 in the expression of f(x):

f(2) = 6^2

f(2) = 36

**The result of composition of the functions is: (f o g)(36) = 36.**