What are the extreme values of f(x) = 3x^3 + 9x + 1

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The function f(x) = 3x^3 + 9x + 1. The extreme values of f(x) lie at points that are the solution of the equation f'(x) = 0

f'(x) = 9x^2 + 9

f'(x) = 0

=> 9x^2 + 9 = 0

=> x^2 = -1

This equation does not have a real solution.

The given function does not have any extreme points. It can take on nay value in the set `(-oo, oo)`

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