What is the equation in standard form of a perpendicular line that passes through (5,1)

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Let line `L_1` posses through (5,1) has slope m.

Thus any line `L_2` passes through (5,1) and perpendicular to `L_1` has slope (-1/m).

Thus equation of line `L_2` is

`y-1=(-1/m)(x-5)`

`my-m=-(x-5)`

`x+my=5+m`

which is standard form of equation of line.

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