What is the equation for a parabola with a vertex of (5,-2) and a point (6,1)?    Include "y=" as part of your answer. 

1 Answer | Add Yours

lemjay's profile pic

Posted on

To determine the equation, use the vertex form of the parabola which is:

`y=a(x-h)^2+k`

Plug-in the given vertex (5,-2).

`y=a(x-5)^2+(-2)`

`y=a(x-5)^2-2`

To get the value of a, plug-in the point (6,1).

`1=a(6-5)^2-2`

`1=a(1)^2-2`

`1=a-2`

`1+2=a-2+2`

`3=a`

Hence, the equation of the parabola is `y=3(x-5)^2-2` .

We’ve answered 330,852 questions. We can answer yours, too.

Ask a question