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What is the equation of the mirror image of the line 3x + 2y = 16 about the y-axis.

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lxsptter | Student, Undergraduate | Valedictorian

Posted April 29, 2013 at 4:03 AM via web

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What is the equation of the mirror image of the line 3x + 2y = 16 about the y-axis.

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted April 29, 2013 at 4:09 AM (Answer #1)

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The equation of the line 3x + 2y = 16 can be rewritten as y = (-3/2)x + 8. This line has a slope of -3/2 and a y-intercept of 8.

The mirror image of the line about the y-axis is one with slope -(-3/2) = 3/2 and the same y-intercept.

This gives the equation of the line as: y = (3/2)*x + 8

=> 3x - 2y + 8 = 0

The graph of the original line 3x + 2y = 16 (in black ) and the mirror image 3x - 2y + 8 = 0 (in red) are given below:

The required equation of the mirror image is 3x - 2y + 8 = 0

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