What is the equation of the line with slope 1/7 and y-intercept 3/4 and the slope between points (-1, 2) and (9, 7).

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Equation of the line with slope 1/7 and y intercept 3/4.

Write equation in form of

y=mx+c

y=(1/7)x+3/4

y=(4x+21)/28

28y=4x+21

Slope between the points (-1,2) and (9,7) is

`m=(7-2)/(9+1)`

`=5/10=1/2`

Write the equation of a line with slope `1/7` and y-intercept of `3/4.`

If using slope-intercept form `(y=mx+b)` , the equation of the line is `y = 1/7x + 3/4`

If the equation is needed in standard form `(ax + by = c)` , the equation is: `4x - 28y = -21.`

**The solution is: `y = 1/7x + 3/4` or `4x - 28y = -21` **

Find the slope between (-1, 2) and (9, 7).

`Slope = "rise"/"run"` or `(Deltay)/(Deltax)`

`(7 - 2)/ (9 - -1)` = `5/10 = 1/2`

**The slope between the 2 points is `1/2.`**

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