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What is the equation of the line with slope 1/7 and y-intercept 3/4 and the slope...

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zarawhat | eNotes Newbie

Posted October 5, 2013 at 3:26 AM via web

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What is the equation of the line with slope 1/7 and y-intercept 3/4 and the slope between points (-1, 2) and (9, 7).

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aruv | High School Teacher | (Level 2) Valedictorian

Posted October 5, 2013 at 3:32 AM (Answer #1)

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Equation of the line with slope 1/7 and y intercept 3/4.

Write equation in form of

y=mx+c

y=(1/7)x+3/4

y=(4x+21)/28

28y=4x+21

Slope between the  points (-1,2) and (9,7) is

`m=(7-2)/(9+1)`

`=5/10=1/2`

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baxthum8 | High School Teacher | (Level 3) Associate Educator

Posted October 5, 2013 at 12:14 PM (Answer #2)

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Write the equation of a line with slope `1/7`  and y-intercept of `3/4.`

If using slope-intercept form `(y=mx+b)` , the equation of the line is `y = 1/7x + 3/4`

If the equation is needed in standard form `(ax + by = c)` , the equation is:  `4x - 28y = -21.`

 The solution is: `y = 1/7x + 3/4` or `4x - 28y = -21`

Find the slope between (-1, 2) and (9, 7).

`Slope = "rise"/"run"` or `(Deltay)/(Deltax)`

`(7 - 2)/ (9 - -1)` =  `5/10 = 1/2`

The slope between the 2 points is `1/2.`

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