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What is the equation of the line that passes through (3,2) and is perpendicular to the...

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greynose | Student, Undergraduate | Honors

Posted August 7, 2011 at 11:48 PM via web

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What is the equation of the line that passes through (3,2) and is perpendicular to the line 2x+y-1=0?

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giorgiana1976 | College Teacher | Valedictorian

Posted August 7, 2011 at 11:51 PM (Answer #1)

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If two lines are perpendicular, then the product of their slopes is -1.

We'll put the given equation of the line in the slope intercept form:

y = mx + n

y = -2x + 1

Comparing both equations, we'll get the slope m = -2.

The slope of the perpendicular line is m1 = 1/2

The equation of the line that is passing through the point (3,2) and it has the slope m1 = 1/2, is:

y - 2 = (1/2)*(x-3)

y - 2 = x/2 - 3/2

y = x/2 - 3/2 + 2

y = x/2 + 1/2

The requested equation of the perpendicular line is y = x/2 + 1/2.

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