What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? Show your work. (µC = 1.0 × 10–6 C)
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To solve for the electric force, apply Coulomb's Law formula which is:
`F= | (kq_1q_2)/r^2|`
where F - electric force (in Newton) ,
q1 and q2 - are the charges (in Coulomb),
r - distance between q1 and q2 ( in meters), and
k - electrostatic constant `9xx10^9 N*m^2/C^2` .
So, convert 5.0 cm to meters.
Also, convert the given charges to Coulombs.
Then, plug-in `k=9xx10^9` , `q_1=+2xx10^(-6)` , `q_1=-2xx10^(-6)` and `r=0.05` to the formula.
Hence, the electric force between the given charges is 14.4N.
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