What is the elctron configuration of Titanium and Manganese?
I'm making a periodic table and when I look up the electron configuration(the short version) Titanium(Ti) and Manganese(Mn) they have the same electron configuration and I dont know why that is so could someone please tell me what the correct way to write it and if you wouln't mind how you found it.Thanks so much!!
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Titanium and Manganese are both Transition Metals that are in Period 4 (row 4) of the periodic table. Because they are in period 4 they both have 4 energy levels of electrons. They do not have the same electron configurations. The general electron configuration for a neutral atom of Titanium that has 22 protons and 22 electrons is 2, 8, 10, 2. The general electron configuration for a neutral atom of Manganese that has 25 protons and 25 electrons is 2. 8, 13, 2. The complete configuration for Titanium reads: 1s2, 2s2, 2p6, 3s2, 3p6, 3d2, 4s2. The complete configuration for Manganese reads: 1s2, 2s2, 2p6, 3s2, 3p6, 3d5, 4s2 . The short hand for Titanium is [Ar] 4s2 3d2. The shorthand for Manganese is [Ar] 4s2 3d5. The shorthand system is based on the Noble Gases. Both Titanium and Manganese have 2 electrons in their last energy level like many of the Transiton Metals. To make things more complicated there is yet another way to write the configurations based on the order in which the energy levels are filled, but let's leave that for now!
Titanium: `1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2`
Short ver: [`Ar] 4s^2 3d^2`
Manganese reads: `1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5`
short ver: `[Ar] 4s^2 3d^5`
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