What is domain of arctg 1/(x^2-9)?

1 Answer | Add Yours

sciencesolve's profile pic

Posted on

You need to remember that the domain of the arctangent function comprises all real numbers, hence, you need to consider the following condition for the principal argument `1/(x^2 - 9)` such that:

`1/(x^2 - 9) in R => x^2 - 9 != 0 => x^2 != 9 => x_(1,2) != +-3`

Hence, evaluating the domain of the given function yields `x in R - {-3,3}.`

Sources:

We’ve answered 319,846 questions. We can answer yours, too.

Ask a question