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What is the distance of the point (6, 8) from the center of the circle x^2 + y^2 = 48.

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What is the distance of the point (6, 8) from the center of the circle x^2 + y^2 = 48.

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The distance of the point (6, 8) from the center of the circle x^2 + y^2 = 48 has to be determined.

The general equation of a circle with center (h, k) and radius r is `(x-h)^2 + (y-k)^2 = r^2` . The center of the circle x^2 + y^2 = 48 is (0, 0). The distance between two points `(x_1, y_1)` and `(x_2, y_2)` is `sqrt((x_2 - x_1)^2 + (y_2-y_1)^2)` .

For the points (0,0) and (6,8) the distance is `sqrt(6^2 + 8^2)` = `sqrt(100)` = 10

The distance of the point (6, 8) from the center of the circle x^2 + y^2 = 48 is 10 units.

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