Better Students Ask More Questions.
What is the distance of the point (3,4) from the line 3x - 8y = 14
1 Answer | add yours
The distance of a point (X, Y) from a line ax + by + c = 0 is given by `|a*X+b*Y+c|/sqrt(a^2+b^2)`
The distance of the point (3, 4) from the line 3x - 8y - 14 = 0 is:
`|3*3 - 8*4 - 14|/sqrt(3^2+8^2)`
= `|9 - 32 - 14|/sqrt 73`
= `37/sqrt 73`
The required distance of the point from the line is` 37/sqrt 73` .
Posted by justaguide on June 20, 2013 at 5:08 AM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.