What is the distance of the point (3,4) from the line 3x - 8y = 14

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The distance of a point (X, Y) from a line ax + by + c = 0 is given by `|a*X+b*Y+c|/sqrt(a^2+b^2)`

The distance of the point (3, 4) from the line 3x - 8y - 14 = 0 is:

`|3*3 - 8*4 - 14|/sqrt(3^2+8^2)`

= `|9 - 32 - 14|/sqrt 73`

= `37/sqrt 73`

**The required distance of the point from the line is` 37/sqrt 73` .**

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