# What is the discriminant of x^2=4?Please show steps on how you got that answer.

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Given a quadratic equation in standard form `ax^2+bx+c=0` , the discriminant is `b^2-4ac` .

Rewriting `x^2=4` in standard form we get:

`x^2-4=0` where a=1,b=0,c=-4

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**The discriminant is `0^2-4(1)(-4)` or 16**

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**Sources:**

`x^2=4` to find the discriminant use the formula `b^2-4ac`

the first thing is to take away `4`

`x^2-4=4-4`

`x^2-4=0`

`a=1 ` b would be 0 as there is no b value `c=-4` plug in these numbers

`0^2-4(1)(-4)` simplify it

0+16 set it up as an equation

`0+16=16 ` so the **discriminant is 16 and the problem has 2 real solutions**