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What is derivative of sin(x^2+ln2)?
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You need to use the chain rule to find the derivative of the given function.
`f(x) = sin(x^2+ ln2)`
Differentiating with respect to x yields:
`f'(x) = (sin(x^2+ ln2)'*(x^2 + ln 2)'=gtf'(x) = (cos(x^2+ ln2))`
`(2x+0)` `f'(x) = 2x*cos(x^2+ ln2)`
Differentiating the given function with respect to x yields`f'(x) = 2x*cos(x^2+ ln2)` .
Posted by sciencesolve on December 16, 2011 at 12:05 AM (Answer #1)
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