What is derivative of sin(x^2+ln2)?



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Posted on (Answer #1)

You need to use the chain rule to find the derivative of the given function.

`f(x) = sin(x^2+ ln2)`

Differentiating with respect to x yields:

`f'(x) = (sin(x^2+ ln2)'*(x^2 + ln 2)'=gtf'(x) = (cos(x^2+ ln2))`

`(2x+0)` `f'(x) = 2x*cos(x^2+ ln2)`

Differentiating the given function with respect to x yields`f'(x) = 2x*cos(x^2+ ln2)` .

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